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3 years ago

Nikhil drew a picture of an open greeting card on his paper. What is the total area of the drawing of the open greeting card?

Mathematics

1 answer:

Schach [20]3 years ago

6 0

Answer:

35 in2

Step-by-step explanation:

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the average rainfall in Clearview is 38 inches . this year 29.777 inches fell . How much less rain fell this year than falls in

dexar [7]

38 (average) - 29.777 (this year) = 8.223 inches less this year than the average year.

6 0

4 years ago

If it is a fraction, then it is a number between zero and one. What is an appropriate counterexample?

Nimfa-mama [501]

Answer:

1/2

Step-by-step explanation:

As a decimal it is 0.5 which is exactly between 0 and 1

Hope this helps you :) !

5 0

3 years ago

Question 11 point(s) Jared made Ask Your Teacher cups of snack mix for a party. His guests ate Ask Your Teacher of the mix. How

liq [111]

Answer:

$8\frac{1}{2}$ cups

Step-by-step explanation:

To determine the quantity of snack mix Jared guest ate, we multiply the quantity of snack mix the guest ate by the quantity of snack mix Jared made. i.e we determine $\frac{2}{3}of12\frac{3}{4}$ by multiplying both fractions together

quantity of snack mix Jared guest ate = $\frac{2}{3}of12\frac{3}{4}=\frac{2}{3}*12\frac{3}{4}=\frac{2}{3}*\frac{51}{4}=\frac{17}{2} =8\frac{1}{2}$

5 0

3 years ago

How many positive integers $n$ satisfy $ floor sqrt n floor = 5$?

Temka [501]

That's all the square roots of the form 5.xxxx. The numbers start at 5² and end at 6²-1.

So that's 6² - 5² = 11 numbers. We can list them:

25,26,27,28,29,30,31,32,33,34,35

Answer: 11

5 0

3 years ago

I dont understand this

Westkost [7]

Answer:

$\dfrac{1}{2x(x-1)}$

Step-by-step explanation:

Given

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)$

Consider the numerator:

$x^2+2x+1=(x+1)^2$

Consider the denominator:

$x^2-1=(x-1)(x+1)$

Hence, the fraction becomes

$\dfrac{(x+1)^2}{(x-1)(x+1)}=\dfrac{x+1}{x-1}$

Consider the expression in brackets:

$2x^2+2x=2x(x+1)$

Divide:

$\dfrac{x^2+2x+1}{x^2-1}\div (2x^2+2x)=\dfrac{x+1}{x-1}\div 2x(x+1)=\dfrac{x+1}{x-1}\times \dfrac{1}{2x(x+1)}=\dfrac{1}{2x(x-1)}$

4 0

3 years ago