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3 years ago

What are the solutions to the equation x2 = 9? Explain why is more than one solution to the equation.

Mathematics

1 answer:

Firdavs [7]3 years ago

6 0

ANSWER

$x = - 3 \: \: or \: \: x = 3$

The degree is two so it must have more than one solution.

EXPLANATION

The given equation is

${x}^{2} = 9$

Let us use the square root method to solve this equation.

Since the degree of x is two, the <em>fundamental theorem of algebra</em> says it must have 2 roots.

We take square root to obtain,

$x = \pm \sqrt{9}$

$x = \pm3$

Split the plus or minus sign to obtain,

$x = - 3 \: \: or \: \: x = 3$

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harina [27]

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3 years ago

A couple quick algebra 1 questions for 50 points!

kkurt [141]

Answer:

Question 6) Neither (Not an inverse variation)

Question 7) Inverse variation

Question 8) Inverse variation

Step-by-step explanation:

These are the two formulas we need to know prior to solving the question.

Direct variation: c times x

Inverse variation: c times 1/x --> c/x

- Here, c is the constant

6. y = x + 7

This is neither. It is not in the form of a direct, or inverse variation, so it does not belong in any category.

7. 14 = xy

This equation is an inverse variation.

xy = 14

y = 14/x

14 is the constant, and the format is the same as for an inverse variation.

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This equation is an inverse variation.

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So we can conclude that questions 7 and 8 is an inverse variations, while question 6 isn't.

6 0

2 years ago

Read 2 more answers

How to put 50,000,000 in standard form?

SVEN [57.7K]

Answer:

50,000,000 is in standard form.

Step-by-step explanation:

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2 years ago

A. Plot 13.58 on a number line on which the long

Lerok [7]

Answer:

Se attached for plots and here is position of the numbers:

a. Plot 13.58 on a number line on which the long

tick marks are whole numbers.

13 < 13.58 < 14

b. Plot 0.193 on a number line on which the long

tick marks are tenths.

0.1 < 0.193 < 0.2

c. Plot 26.9999 on a number line on which the

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26.999 < 26.9999 < 27.000

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3 years ago

A box contains 144 marbles, which are either red or blue. if there are 3 times as many red marbles as there are blue marbles in

kicyunya [14]

Given:
X: The blue marbles.
3X: The red marbles.
A box contains 144 marbles.
SOLVING:
X + 3X = 144
4X = 144
X = $\frac{144}{4}$
X = 36 ===> The blue marbles.

If there are 3 times as many red marbles as there are blue marbles:
3(36) = 108 ===> The red marbles. SOLUTION

TESTING:
$36+108=144$
$\boxed{144}=\boxed{144}\quad\checkmark\ The\ value\ is\ correct.$
GOOD LUCK...!!!

3 0

3 years ago