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sveticcg [70]
3 years ago
8

whats another way to write (s-6)(s+1) when s represents the side of a square and the equation represents the area of a rectangle

?
Mathematics
1 answer:
viktelen [127]3 years ago
8 0

The another way to write (s - 6)(s + 1) is s² - 5s - 6

Step-by-step explanation:

Let us revise how multiply two binomial (a + b)(x + y)

  • Multiply the 1st terms
  • Multiply the 2nd terms
  • Multiply the nears and extremes, where nears are the 2nd term of first bracket and 1st term in the second bracket, the extremes are the 1st term in the first bracket and the 2nd term in the second bracket
  • Add the like terms if necessary

∵ The area of the square = (s - 6)(s + 1)

- To find the another way multiply the two brackets

∵ s × s = s²

∵ -6 × 1 = -6

∵ -6 × s = - 6s ⇒ nears

∵ s × 1 = s ⇒ extremes

- The terms - 6s and s are like terms, then add them

∵ - 6s + s = - 5s

∴ (s - 6)(s + 1) = s² - 5s - 6

∴ The area of the square = s² - 5s - 6

The another way to write (s - 6)(s + 1) is s² - 5s - 6

Learn more:

You can learn more about the binomials in brainly.com/question/2334388

#LearnwithBrainly

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Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

V_1=\dfrac{2}{3}\pi r^3

Where, r is the radius of the hemisphere.

V_1=\dfrac{2}{3}(3.14)(6)^3

V_1=\dfrac{6.28}{3}(216)

V_1=452.16

Volume of cylinder is:

V_2=\pi r^2h

Where, r is the radius of the cylinder and h is the height of the cylinder.

V_2=(3.14)(6)^2(12)

V_2=(3.14)(36)(12)

V_2=1356.48

We know that,

l^2=r^2+h^2                               [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

(10)^2=(6)^2+h^2

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\sqrt{64}=h

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Volume of cone is:

V_3=\dfrac{1}{3}\pi r^2h

Where, r is the radius of the cone and h is the height of the cone.

V_3=\dfrac{1}{3}(3.14)(6)^2(8)

V_3=\dfrac{25.12}{3}(36)

V_3=301.44

Now, the volume of the combined figure is:

V=V_1+V_2+V_3

V=452.16+1356.48+301.44

V=2110.08

Therefore, the volume of the given figure is 2110.08 cubic units.

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