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garri49 [273]
3 years ago
15

Jay and Blair went fishing. Together, they ccaight 27 fish. Jay caught 2 times as many fish as Blair. How many fish did Jay and

Blair each catch?
Mathematics
1 answer:
Llana [10]3 years ago
3 0
Jay caught 18 fish and Blair caught 9.
Here's why.

Jay caught 2 times as many as blair. So let's say the fish caught by blair is represented by the variable, x. The number of fish caught by Jay would then be 2x.
So, 27 is the number of fish they both caught together.  So then...
27=x+2x
This equation can be simplified to be 27=3x.
So, we'll need to find the value of x first. Divide each side by 3 to get the x by itself. 27/3 is 9. 3x/3 is x. So 9=x.
We now have the number of fish Blair caught, so to get the number jay caught, we double this number.  9 times 2 is 18, so Jay caught 18 fish and Blair caught 9.


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Step-by-step explanation:

The given is,

           x+3y=5......................................(1)

           x-3y=-1....................................(2)

Step:1

         By elimination method,

        Subtracting Equations (1) and (2),

                     x+3y=5

                     x-3y=-1

             ( - )

           ( x-x ) + ( 3y+3y ) = ( 5 +1 )

                                       6y = 6

                                         y = 1

Step:2

        Substitute the value of y in equation (1),

                             x+3y=5

                       x + ( 3 × 1 ) = 5

                                      x = 5-3

                                      x = 2

Step:3

        Check for Solution,

        Substitute the values of x and y in Eqn (1),

                                  x+3y=5

                           2 + ( 3 × 1 ) = 5

                                         5 = 5

Result:

       The solution for the given equations  x + 3y = 5 and x - 3y = -1 are x=2 and y=1, by elimination method.

7 0
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