Answer:
1.
-3|2x+6|=-12
|2x+6|=4
2x+6=4
2x+6=-4
x1=-5, x2=-1
2.
|x-2|+10=12
|x-2|=12-10
|x-2|=2
x-2=2
x-2=-2
x1=0, x2=4
F(x)=x^5 + 5*x^4 - 5*x^3 - 25*x^2 + 4*x + 20
By examining the coefficients of the polynomial, we find that
1+5-5-25+4+20=0 => (x-1) is a factor
Now, reverse the sign of coefficients of odd powers,
-1+5+5-25-4+20=0 => (x+1) is a factor
By the rational roots theorem, we can continue to try x=2, or factor x-2=0
2^5+5(2^4)-5(2^3)-25(2^2)+4(2)+20=0
and similarly f(-2)=0
So we have found four of the 5 real roots.
The remainder can be found by synthetic division as x=-5
Answer: The real roots of the given polynomial are: {-5,-2,-1.1.2}
Answer:
i think the answer is b
Step-by-step explanation:
D
this is because there are 27 total students and 3 groups. let x represent the number of students per group. the equation would be 3(x)=27
if u need to solve for x, it would be x =9
Answer:
The answer is 2
Step-by-step explanation:
Multiply the numerator and denominator by the conjugate.
