Factor completely: 9x10 + 121y8

Solve the equation 6-x-x=18 A. -6 B. 6 C. 9 D. -9

Veronika [31]

A. x = -6
6-x-x = 18
6-2x =18
-2x = 12
x = -6

4 0

3 years ago

What expressions represent 5/6 × 5

pickupchik [31]

Answer:

$5 \div 6 \times 5 = 25\div 6$

<h2>25/6 is the Answer</h2>

7 0

2 years ago

The present value of an ordinary annuity of $350 each year for five years, assuming an opportunity cost of 4 percent, is ___

liubo4ka [24]

We can calculate it by PVOA table.
PVOA means present value of an ordinary annuity.
PMT = $350
PMT means recurring payment.
time = 5 years and interest rate is 4%
So n = 5 and i = 4%
So we can calculate PVOA as

PVOA = PMT times (PVOA factor for n = 5 and i = 4%)
$= 350 * (4.452)$ (PVOA factor PVOA table)
$= 1558.2$
So present value is $1558.2

4 0

3 years ago

The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of X is N (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable X is defined as the amount of sodium consumed.

The random variable X has an average value of, μ = 9.8 grams.

The standard deviation of X is, σ = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable X follows a normal distribution with parameters μ = 9.8 grams and σ = 0.8 grams.

Thus, the distribution of X is N (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (X) to z-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of z as follows:

$P(-z$

The value of z for P (Z < z) = 0.65 is 0.39.

Compute the value of x₁ and x₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

4 0

2 years ago

Please help someone

DiKsa [7]

The first equation is x = -1

The second and third equations are no solution

The third equation is all rel numbers.

We can tell each one by solving them. In the first one, you get the following.

4 + x = -8x - 5 ----> Add 8x to both sides

4 + 9x = -5 ----> Subtract 4 from both sides

9x = -9 ----> Divide both sides by 9

x = -1

For the middle two, when you attempt to solve, you get untrue statements. This shows there are no solutions. See the example below.

7 + 2x = 2x - 7 ----> Subtract 2x from both sides

7 = -7 (UNTRUE)

And for the last one, each term cancels out, which shows that we have all real solutions.

-3x + 3 = 3( 1 - x) ----> Distribute the 3

-3x + 3 = 3 - 3x ----> Add 3x to both sides

3 = 3 (TRUE)

8 0

2 years ago