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3 years ago

Simplify this expression x² x x x x

1 answer:

7 0

Although x ² and x both have the variable x, you can’t add them together. So x + x + x + x is 4x and we just leave x ² the same. So the simplified expression is x ² + 4x. I hope this helped!!

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find an expression for the area of a rectangle of sides 2x+3 and x-1 given that the perimeter is 28cm what is the value of x

Ierofanga [76]

Answer:

4cm

Step-by-step explanation:

Given data

L=(2x+3)

W=(x-1)

P=28cm

A= L*W

A= (2x+3)*(x-1)

open bracket

A= 2x^2-2x+3x-3

collect like terms

A= 2x^2+x-3

P= 2L+2W

P= 2*(2x+3)+2(x-1)

P= 4x+6+2x-2

collect like terms

P= 6x-4

but p= 28

28= 6x-4

28-4= 6x

24= 6x

x= 24/6

x= 4cm

Hence x= 4cm

4 0

2 years ago

Solve for x -12 = 4(x – 5) X =

bonufazy [111]

Answer:

-12=4x-20

4x=12+20

4x=32

4 = 4

x=8

5 0

3 years ago

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

6 0

2 years ago

Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29

Alexeev081 [22]

Answer:

a) x = 3

b) z = 10

c) p = 2

d) x = 7

e) u = 1

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

x = 3

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

z = 10

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

p = 2

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

x = 7

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

x = 1

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0

2 years ago

How to turn this equation: y= -1.02(x-3)^2+9.25 into factored form

MatroZZZ [7]

Answer:

$y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})$

Step-by-step explanation:

You first equate it to zero to get:

$-1.02(x-3)^2+9.25=0$

Then solve using square root method

$-1.02(x-3)^2=-9.25$

$(x-3)^2=\frac{-9.25}{-1.02}$

$(x-3)^2=\frac{925}{102}$

$x=3\pm\sqrt{\frac{925}{102}}$

$x=3\pm{\frac{5\sqrt{3774}}{102}}$

$x={\frac{306\pm5\sqrt{3774}}{102}}$

Now work it backwards

$102x-(306\pm5\sqrt{3774})=0$

$(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})=0$

Hence the factored form is:

$y=(102x-306-5\sqrt{3774})(102x-306+5\sqrt{3774})$

8 0

2 years ago