Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
Never because one of them goes 1k8 and one of them goes 24 so if they that song every time then it would be the same time diffrence even if you try a million tinmes
Step-by-step explanation:
In order to solve by elimination, let's multiply the first equation by -2. This way, when we add the equations, the variable y will be canceled out:
Now, adding the equations, we have:
Now, calculating the value of y, we have:
Therefore the solution is (3, 0).
Answer:
There's 21% of chances
Step-by-step explanation:
Here we have to use the definition of a simple probability, where all fishes has the same probability to be chose.
So, we have to divide the possible outcomes with the total of outcomes. The possible outcomes refer to the number of large-blue fishes, and the total number of outcomes represent the total number of fishes. So
P = 3/4 ≈ 0.21 (or 21%)
Therfore, there's 21% of chances to select one fish randomly and be a large, blue fish.
Answer:
So I am not sure my answers are correct but I hope they help:
A. y = 6x+14
B. 6 people
