Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.
To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.
A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:
Similarly, but exchanging the role of x and y, we compute the length of BC:
So, the area of the rectangle is 
The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:
So, the area of the portion located in the third quadrant is 
This means that the ratio between the two area is
If we want this ratio to be a percentage, just make sure that the denominator is 100:
<span>We need to calculate noon sun angle. Noon sun angle is an angle at which sun-rays fall at noon on a given date.
</span>On September 22, the sun’s rays form a 90° angle at noon at the equator.
Formula for calculating noon sun angle is:
Noon_sun_angle = 90° - Zenith angle
We have complementary angles so we need to substract zenith angle from 90°.
The zenith angle is the distance between subsolar point (point where sun is at 90°) and the latitude of an observer. In our case this angle will have same value as latitude because subsolar point is at equator 0°. If our latitude and subsolar point are at same hemisphere we substract values. Otherwise we add values.
New Orleans, USA
Latitude = 30°
Noon_sun_angle = 90° - 30° = 60°
Helsinki, Finland
Latitude = 60°
Noon_sun_angle = 90° - 60° = 30°
1. Angle PAB is 90 degrees, as it is formed from the tanget to the circle at A, and the radius drawn to A.
2. AB=BC, because tangents drawn to a circle from the same point are equal.
3. PB is Common, so by the side-side-side congruence postulate, triangles ABP and CBP are congruent.
4. So measure of m(BPA)=x/2 and m(ABP)=73/2.
5.
, x= 107 degrees.
Answer:
A).Amount = $218250
B). Amount = $88700
Step-by-step explanation:
A) .$5000 in an account at age 23, and withdraw it 42 years
Number of years t= 42 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 42
A= p(1+r/n)^(nt)
A= 5000(1+0.09/42)^(42*42)
A= 5000(1+0.002143)^(1764)
A= 5000(1.002143)^1764
A= 5000(43.65)
A= 218250
Amount = $218250
B).waits 10 years before making the deposit, so that it stays in the account for only 32 years
Number of years t= 32 years
Principal P = $5000
Rate r= 9%
Number of times compounded n= 32
A= p(1+r/n)^(nt)
A= 5000(1+0.09/32)^(32*32)
A= A= 5000(1+0.0028125)^(1024)
A= 5000(1.0028125)^1024
A= 5000(17.74)
A= 88700
Amount = $88700
Answer:
answer is of left to right
16x^14/(36x^2)=4x^12/9
(3^3)×(x^5)×y÷4
-9a^3(b^5)
