Answer:
Multiply
Step-by-step explanation:
Bear in mind that the area of a "parallelogram" is base * height.
notice the picture, the front and back parallelograms, have an altitude/height of 3 cm, and a base of 8 cm, so the area of one of those two is 3*8.
as far as the left and right parallelograms, they have a base of 7 cm, but the altitude is also 3 cm, so the area of one of those is 3 *7.
bear in mind the altitude/height is the distance from the base to the top, and in this case is just 3 cm.
anyway, you have 4 parallelograms, get the area of each, add them up, and that's the surface area of the figure.
2(3*8) + 2(3*7).
Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of 
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
Hello. I cannot see the images if you show them I’ll answer
Step-by-step explanation:
F(x) = ∫ₐˣ t⁷ dt
F(x) is the area under f(t) between t=a and t=x. When x=a, the width of the interval is 0, so the area is zero.
F(6) = 0, so a = 6.
F(x) = ∫₆ˣ t⁷ dt
F(6) = ∫₆⁶ t⁷ dt
F(6) = 0
