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2 years ago

Elizabeth can type 250 words in 5 minutes. What are the units? Your answer

Mathematics

1 answer:

Vaselesa [24]2 years ago

8 0

Answer: 50 words per minute

Step-by-step explanation:

250 words per 5 minutes DIVIDE BOTH NUMBERS BY 5

50 words per 1 minute

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A family has 2 cars. the first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of 2

lora16 [44]

Car 1: 15x

Car 2: 20y

15x+20y=1300

x+y=75

So y=75-x

15x+20(75-x)=1300

-5x+1500=1300

-5x=-200

x=40.

y=75-40

y=35

Car 1: 40 gallons

Car 2: 35 gallons

8 0

2 years ago

Can someone assist me with these Algreba questions olease?

Delicious77 [7]

the answer have to be would be (-3, 1)

4 0

3 years ago

What is the area of this triangle?

dsp73

Answer:60

Step-by-step explanation:

a=13 b=13 c=10

Perimeter of =a+b+c

perimeter of =13+13+10

Perimeter of =36

S=36 ➗ 2

S=18

Area=√s(s-a)(s-b)(s-c)

Area=√18(18-13)(18-13)(18-10)

Area=√18(5)(5)(8)

Area=√(3600)

Area of =60

4 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

EleoNora [17]

Answer:

0, 10

Step-by-step explanation:

The given function is:

$g(y) = \frac{y-5}{y^2-3y+15}$

According to the quotient rule:

$d(\frac{f(y)}{h(y)}) = \frac{f(y)*h'(y)-h(y)*f'(y)}{h^2(y)}$

Applying the quotient rule:

$g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}$

The values for which g'(y) are zero are the critical points:

$g'(y)=0=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}\\(y-5)*(2y-3)-(y^2-3y+15)=0\\2y^2-3y-10y+15-y^2+3y-15\\y^2-10y=0\\y=\frac{10\pm \sqrt 100}{2}\\y_1=\frac{10-10}{2}= 0\\y_2=\frac{10+10}{2}=10$

The critical values are y = 0 and y = 10.

5 0

3 years ago

1. Graph the function f(x)=4cos(x). (Be sure to label your x-axis.)

Mekhanik [1.2K]

ANSWER

To graph the function

$y=4cos(x)$ we need to plot some few points within one period. Since the interval is not given, we shall use $[0,2 \pi]$ '

$\left \begin{array}{cc}x&y=4cos(x)\\0 &4\\\frac{\pi}{2}&0 \\ \pi&-4\\\frac{3\pi}{2} &0\\2\pi&4\end{array}\right$ .

We plot the above points to obtain the graph as shown in the attachment.

6 0

3 years ago