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KatRina [158]
3 years ago
5

What is the gcf for 84 and 54

Mathematics
1 answer:
solmaris [256]3 years ago
3 0
Your answer for the greatest common factor is 6
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What two numbers add up to 10 and multiply to 21
WITCHER [35]

Answer:The answer is 3 & 7

Step-by-step explanation:3 x 7 = 21

3 + (7) = 10

Are you asking because you are trying to figure out how to factor the following quadratic equation?

x2 + 10x + 21 = 0

If so, the solution to factor the quadratic equation above is:

(X + 3 ) (X + 7)

To summarize, since 3 and 7 multiply to 21 and add up 10, you know that the following is true:

x2 + 10x + 21 = (X + 3 ) (X + 7)

3 0
3 years ago
Which is the simplified form of m^-8p^0
kipiarov [429]

Answer:

1 /m ^8

Step-by-step explanation:

Hope this helps

<h2><em>:)</em></h2>
5 0
3 years ago
Read 2 more answers
ARST was
algol [13]

Answer:

translate

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me. This is real confusing. ​
katrin2010 [14]

Answer:

1st problem: b) A=2500(1.01)^{12t}

2nd problem:  c) A=2500e^{.12t}

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

A=P(1+\frac{r}{n})^{nt}

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

A=2500(1+\frac{.12}{12})^{12t}

Time to clean up the inside of the ( ).

A=2500(1+.01)^{12t}

A=2500(1.01)^{12t}

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

A=Pe^{rt}

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

A=2500e^{.12t}.

6 0
3 years ago
What is the measure of angle G?
Allushta [10]

Answer:

28

Step-by-step explanation:

8 0
3 years ago
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