Answer:
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Step-by-step explanation:
Given:
Volume of inside of the sphere is given as

where r is the radius of the sphere
To Find:
r =?
Solution:
We have
......Given
![3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}](https://tex.z-dn.net/?f=3%5Ctimes%20V%3D4%5Cpi%20r%5E%7B3%7D%20%5C%5C%5C%5C%5Ctherefore%20r%5E%7B3%7D%3D%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%20%5C%5C%5C%5C%5Ctherefore%20r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D%20%5Ctextrm%7Bwhich%20is%20the%20expression%20for%20r%7D)
Therefore,
![r=\sqrt[3]{\frac{3V}{4\pi }}](https://tex.z-dn.net/?f=r%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3V%7D%7B4%5Cpi%20%7D%7D)
is the required r
Answer:
You didnt identify the volume so we can find the radius
Step-by-step explanation:
lol
Answer:
See explaination
Step-by-step explanation:
Probability is the number of desired outcomes over the total outcomes.
1) You want to find Oranges, so that is your desired outcome:
There are 4 oranges in the bowl.
Now sum up all the fruits to get the total:
9+4+7+3+6 = 29
Therefore you have 4/29
2) Same idea, count the peaches and put it over total:
3/29
3) This time, you still want to use the same idea, but its just your desired outcomes that have increased. So instead of just having one fruit, now you want to add the total of 2 fruits as your desired outcome.
(9+4)/29
= 13/29
4) To find the probability of a fruit other than a plum, you can use complementary counting. Since the maximum probability is one, we can find what we dont want, and the outcome of that subtracted from one must be the results that we want.
So a plum is 6/29
1-6/29 = 23/29
5) Same idea as what is used in problems 3 and 4, just a combination of the 2.
(4+3)/29
1-7/29
= 22/29
I can help you what problem??
Answer:
D h(x) = f(x)×g(x)
Step-by-step explanation:
h(x) has a wave with 2 changes in direction.
so, this needs to be an expression of the third degree (there must be a term with x³ as the highest power of x).
and that is only possible when multiplying both basic functions. all the other options would keep it at second degree (x²) or render it even to a first degree (linear).