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3 years ago

Pls help me and hve a nice day ;p

Mathematics

1 answer:

Art [367]3 years ago

3 0

Step-by-step explanation:

km²

make it braintliest please

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Please help me with this question

777dan777 [17]

Answer:

Step-by-step explanation:

102 divided by 2 is 51

3 0

3 years ago

Read 2 more answers

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $30 and same-day tickets cost

Tju [1.3M]

The advance tickets were 35 in number and the same day ticket will be 30 in number.

<h3>What will be the number of tickets?</h3>

To find out the number of the tickets sold we will give some notations so the notations are as follows:-

A= Cost of advance tickets=$30

S= cost of same-day ticket-=15

$N_A=$ Number of the advance tickets

$N_S=$ Number of same-day tickets.

The equations made by the given data will be:-

$30N_A+15N_S=1500\\\\\\N_A+N_S=65$

By solving the above equations:-

$N_S=30\ \ \ \ \ \ N_A=35$

Hence the advance tickets were 35 in number and the same day ticket will be 30 in number.

To know more about linear equations follow

brainly.com/question/14323743

#SPJ1

7 0

2 years ago

Determine the maximum number of zeros of the polynomial function

IRINA_888 [86]

Answer:

Step-by-step explanation:

6 0

3 years ago

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

3 0

3 years ago

Can someone please help find the answer and explain how you got it please.

tresset_1 [31]

Answer:

Step-by-step explanation:

Hello!

We put in 2 for x and 6 for y

$\frac{2(6)-2}{2}$

Now we can solve this

$\frac{12 - 2}{2}$

$\frac{10}{2} = 5$

The answer is 5

Hope this helps!

4 0

3 years ago

Read 2 more answers