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lukranit [14]
3 years ago
12

Which of the following mathematical operations can be used with functions?

Mathematics
1 answer:
Temka [501]3 years ago
6 0
The correct answers among all the other choices are A) Addition, B) Subtraction, C) Multiplication, and D) Division. These mathematical operations can be used with functions. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
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Select the option that best describes the relationship
WINSTONCH [101]

Answer:

4th one its negative,linear association

Step-by-step explanation:

6 0
2 years ago
What are the partial products that result from multiplying 15x32?
pashok25 [27]
The answer to this question would be: 300; 20; 150; 10

When you multiply 15 x 32, you can divide both numbers into this:
15= 10 + 5
32= 30 +2

Then the multiplication becomes (10+5) * (30+2) which will result in 4 partial product like this:
10*30= 300
10* 2= 20
5* 30= 150
5* 2= 10
7 0
3 years ago
Find x and y <br><br> pls help
Assoli18 [71]

Step-by-step explanation:

(3x+6)= 48(Alternate angles)

3x=48-6

3x=42

x=14

2y+48=5y-9 (Sum of two opposite interior angles= exterior angle)

48+9=5y-2y

57=3y

y=19

8 0
2 years ago
Determine the center and radius of the following circle equation:
-BARSIC- [3]

Answer:

(6, 9 ) and r = 3

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 12x - 18y + 108 = 0

Rearrange the x- terms and the y- terms together and subtract 108 from both sides, that is

x² - 12x + y² - 18y = - 108

To obtain standard form use the method of completing the square

add ( half the coefficient of the x and y terms )² to both sides

x² + 2(- 6)x + 36 + y² + 2(- 9)y + 81 = - 108 + 36 + 81

(x - 6)² + (y - 9)² = 9 ← in standard form

with centre = (6, 9 ) and r = \sqrt{9} = 3

7 0
3 years ago
PLS HELP ME WITH THESE QUESTIONS!
kirill [66]

Answer:

(4, 1/4)

Step-by-step explanation:

Factoring the numerator and the denominator, we have:

6 0
2 years ago
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