Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to . ---> equation (1) By using pythagoras rule which states that the ---> equation (2) where the opposite side's length is 8 and the hypotenuse side's length is 10 by substituting by the values in equation (2) therefore, substitute this value in equation (1) then where A is the area of the square whose side is x
The smallest triangle is not going to be determined by the a plus sign between the largest square and one of the small ones. That eliminates the two top answers.
A right triangle has the pythagorean equation associated with it.
That's a^2 + b^2 = c^2
Both the top right answer and the bottom left answer are eliminated because they are not of this form.
The largest side is c so to find x you need to subtract 8^2 from 10^2
Answer: the perimeter is 214. AB's half is 32.5 and BC's whole is 65
Step-by-step explanation: 10x-5 and 12x-26 are equal, as shown by the marks on their lines, so we can set them equal to each other to solve for x. when solved x=7. then plug 7 into each equation to get 65. lastly add up 84+65+65 to get 214.