See attached image for work.
By analyzing the piecewise function, we conclude that the first graph is the correct one,
<h3>
Which of the following is the graph of the piecewise function?</h3>
The first part of the piecewise function is:
f(x) = √(-x - 2) for x ≤ -2
This parts ends at:
f(-2) = 0
With that, we can discard the last two graphs.
Now, the second part is a rational function with a negative coefficient.
Because of that sign, when x is positive, the function tends to negative infinite near in the asymptote, while when x is negative, the function tends to positive infinite in the asymptote.
Because of that, we conclude that the correct option is the first graph.
If you want to learn more about piecewise functions:
brainly.com/question/3628123
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Answer:
8 seconds
Step-by-step explanation:
Given :
h(t) = -16t2 + initial height
Initial height = 1024 feets
By the time it hits the ground, h(t) = 0
Equation becomes :
0 = - 16t² + 1024
Solve for t
-16t² = 1024
t² = 1024 / -16
t² = 64
t = √64
t = 8
Hence, it will take 8 seconds
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
