How do I find the intervals when it's set up as a fraction?
1 answer:
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Answer:
The required numbers are: 36, 40, 44
Step-by-step explanation:
Let first number = 4x
Second number = 4(x+1)
Third number = 4(x+2)
There sum = 120
We need to find the numbers
We can write:
So, we get x = 9
Now, finding the numbers:
first number = 4x = 4(9) =36
Second number = 4(x+1) = 4(9+1) = 4(10) = 40
Third number = 4(x+2) = 4(9+2) = 4(11) = 44
So, The required numbers are: 36, 40, 44
