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VikaD [51]
3 years ago
5

P + 3 4/5 = 7 l/2 what is p?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
5 0
P = 71/2 - 34/5
P = 355 - 68 / 10
P =287 / 10
P = 28.7
Sergio [31]3 years ago
4 0
P= 7 1/2 - 3 4/5
p=15/2-19/5
p=75/10-38/10
p=37/10
p=3 7/10
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kodGreya [7K]

Answer:

A) 3500

Step-by-step explanation:

C(x) = 0.75x + 3500

C(x) = Total cost

0.75x = variable cost

3,500 = fixed cost

The fixed cost of the function = 3,500

Variable cost refers to cost of production that changes during production such as cost of raw material, wages of workers etc.

Fixed cost are cost of production that remains the same (does not change) with the production process such as building, machineries etc

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7 0
3 years ago
A line that passes through (-7, 5) has a slope of 1/2. Which is another point that the line passes through?
d1i1m1o1n [39]

Answer:

(1, 9)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = \frac{1}{2} and (a, b) = (- 7, 5), hence

y - 5 = \frac{1}{2}(x + 7)

y - 5 = \frac{1}{2} x + \frac{7}{2}

y = \frac{1}{2} x + \frac{17}{2} ← equation of line

To find another point on the line choose any value of x and substitute into the equation for the corresponding y- coordinate

x = 1 : y = \frac{1}{2} + \frac{17}{2} = 9

Thus (1, 9) is another point that the line passes through


8 0
4 years ago
*) Name this triangle by looking at its side lengths.
jenyasd209 [6]

Answer

equilateral

Step-by-step explanation:

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7 0
4 years ago
(x,2) and (6,3); m= -1/2​
makvit [3.9K]
Im not sure what you need answer.. Mind if you specify ?
5 0
3 years ago
Given: ΔABC. If ∠B = 35°, a = 4.5 cm, and b = 6.0 cm, what is the measurement of ∠A to the nearest tenth of a degree?
soldier1979 [14.2K]
We know that

the law of sines established 
a/sin A=b/sin B--------sin A=[a*sin B]/b
a=4.5 cm
b=6 cm
B=35°
so
sin A=[4.5*sin 35°]/6-----> sin A=0.43018
A=arc sin(0.43018)-------> A=25.5°

the answer is the option
<span>C) 25.5° </span>


6 0
3 years ago
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