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Dominik [7]
4 years ago
15

Describe the transformation

Mathematics
1 answer:
xz_007 [3.2K]4 years ago
6 0

Answer:

C.

Step-by-step explanation:

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What is the value of x? Enter your answer in the box. x=
SOVA2 [1]
48 degrees, anything opposite of a degree on the same 2 infinite lines will always be the degree.
8 0
3 years ago
The moon takes 28 days to orbit around the earth going at a distance of 2,413,000. How many kilometers does it take for the moon
Mazyrski [523]

Answer:

As per the statement;

The moon takes 28 days to orbit around the earth going at a distance of 2,413,000 km

From the above information,

The ratio between Distance and Days is; \frac{2413000}{28}

then,

the distance it takes for the moon to travel one day of its orbit around the earth we have;

\frac{2413000}{28} \times 1 = \frac{2413000}{28}=86178.57 km.

Therefore, the distance in kilometer does the moon cover in 1 day is 86178.57 km


8 0
3 years ago
Read 2 more answers
Find the size of the marked angles​
morpeh [17]

Answer:

b = 55°

c = 35°

Step-by-step explanation:

b° = 180° - (85°+40°) = 180° - 125° = 55°

c° = 180° - (b°+90°) = 180° - (55°+90°) = 180° - 145° = 35°

3 0
3 years ago
Read 2 more answers
I'm not sure what trig function to use. Someone please help, and please answer sedulously, and not just for points. Thank you in
Alex Ar [27]

Answer:

w = 6.7451

x = 8.0805

Step-by-step explanation:

Find W

Tan(56) = opposite / adjacent

opposite = 10

Adjacent = w

Tan (56) = 10/w

w*Tan(56) = 10

w = 10 / tan(56)

w = 10/ 1.4826

w = 6.7451

Find x

Tan (34) = 10 / (w + x)

Tan (34) = 0.6745

(w + x) * Tan(34) = 10

w + x = 10 / tan(34)

w+ x = 10 / 0.6745

w + x = 14.826

But we found w = 6.7451

6.7451 + x = 14.826

x = 14l826 - 6.7451

x = 8.0805

7 0
3 years ago
Please help ASAP!
Kruka [31]

First, recall that

\sin(-\theta)=-\sin\theta

So if \sin(-\theta)=\dfrac15, then \sin\theta=-\dfrac15.

Second,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}

We know that \tan\theta>0 and \sin\theta, which means we should also have \cos\theta.

Third,

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}

but as we've already shown, we need to have \cos\theta, so we pick the negative root.

Finally,

\tan\theta=\dfrac{\sin\theta}{\cos\theta}\iff\dfrac6{\sqrt{12}}=\dfrac{-\frac15}{\cos\theta}\implies\cos\theta=-\dfrac1{5\sqrt3}

Unfortunately, none of the given answers match, so perhaps I've misunderstood one of the given conditions... In any case, this answer should tell you everything you need to know to find the right solution from the given options.

6 0
4 years ago
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