Answer:
D) Glucose is needed for cellular respiration
<em><u>Hope this helps!</u></em>
<em><u>Please mark brainliest!</u></em>
Answer: Phosphorylation of mitotic sites at the start of mitosis (N-terminal S22 and C-terminal S392 in human lamin A/C)
Explanation: During mitosis the nuclear lamina is dissociated by phosphorylation- dependent mechanisms that causes conformational changes in structure at N- and C-terminals (non alpha helical terminals) during the start of cellular mitosis that leads to its disassembly. This is because the nuclear lamina has two sites that accept phosphates (phosphoacceptor sites) causing a phosphorylation reaction.
The nuclear lamina is a fibrillar network of intermediate filaments as well as membrane proteins and are involved in DNA replication, cellular division as well as providing mechanical support within the cell.
Answer:
Any animal that is not a equine, tapir, or rhino.
Explanation:
There are 3 extant families of <u>odd toed ungulates</u>:
- Equidae (<em>horses, donkeys, zebras etc</em>)
- Rhinocerotidae (<em>rhinoceroses</em>)
- Tapiridae (<em>tapirs</em>).
If the animal isn't in one of those families, it isn't an <u>odd toed ungulate</u>.
<span>Alfred Wegener first proposed the theory
</span>
It is a bulb
definition: a plant structure with enlarged leaf bases and stored food surrounding a central bit of fleshy stem tissue
