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ruslelena [56]
3 years ago
12

Learn with an example

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

\large{\textbf{f(g(x)) = 20}\\}

Step-by-step explanation:

\large{\textup{Given}:\\$f(x) = 5x $ \hspace{5mm} \& \hspace{5mm} $g(x) = 4x $\\$$ f \circ g(x) = f(g(x))  $$\\$ \implies f(g(x)) = f(5x) $\\\textup{i.e., To substitute $5x$ instead of $x$ in $f(x)$}\\$\implies f(5(x)) = 4(5(x)) = 20x \\ $\textup{Now,}$f(g(1)) = 20(1) =20$}

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3*6.022*10^23 no of molecules in 3.0 moles of sucrose
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A line that includes the points (
barxatty [35]

Answer:

-7

Step-by-step explanation:

Refer to the photo.

the slope=(0-g)/(5-4)

i.e. 7=(-g)/1

g=-7

3 0
3 years ago
The following data points represent the number of players on the Russian Bears volleyball team that were injured in each match t
zvonat [6]

Answer:

its 0=0 1=3 and 2=3

Step-by-step explanation: count how many of the injuries there are for 0. In this case there is none. so how many 1's are there, 3. so put 3 in 1. Now two there is 3 for 2 so put 3 in the 2.

5 0
3 years ago
A philanthropist pledges to donate 10% of a fund each year. If the fund initially has $450,000 how much will
Ann [662]

After 7 years fund balance will be $2152336.05 if the philanthropist pledges to donate 10% of a fund each year.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent. \rm y = a^x

where a is a constant and a>1

We have:

A philanthropist pledges to donate 10% of a fund each year.

We can find the amount left after 7 years as follows:

A = 450000(1 - 0.1)⁷

10% of a fund each year.

Rate r = 10% = 0.1

A = 450000(0.9)⁷

A = $2152336.05

Thus, after 7 years fund balance will be $2152336.05 if the philanthropist pledges to donate 10% of a fund each year.

Learn more about the exponential function here:

brainly.com/question/11487261

#SPJ1

6 0
1 year ago
Which choice is equivalent to the product below when x&gt;0?
V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }

\sqrt{a\\} × \sqrt{b} ⇔ \sqrt{ab}

Given

\sqrt{\frac{6}{x} } × \sqrt{\frac{x^2}{24} }

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x^2}{24}

= \frac{\sqrt{6} }{\sqrt{x} } × \frac{x}{2 \sqrt{6\\} }

Cancel \sqrt{6} on numerator/ denominator

= \frac{1}{\sqrt{x} } × \frac{x}{2\\}

= \frac{1}{\sqrt{x} } × \frac{(\sqrt{x})^2 }{2}

Cancel \sqrt{x} on numerator/ denominator, leaving

= \frac{\sqrt{x} }{2} → D

4 0
3 years ago
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