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Elanso [62]
3 years ago
6

This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc

ent increase in the enrollment? Which operation will you use in your first step?
Mathematics
1 answer:
Ahat [919]3 years ago
4 0

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3><u>Solution:</u></h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

<em><u>The percent increase is given as:</u></em>

\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}

Thus percent increase is 6 %

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