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Allisa [31]
3 years ago
10

Takeru only uses eggs for soufflés in his restaurant. He uses

Mathematics
1 answer:
statuscvo [17]3 years ago
6 0

Question:

Takeru only uses eggs for soufflés in his restaurant. He uses 3 eggs per soufflé. Last week, he bought 4 times as many eggs as he baked soufflés. Takeru had 18 eggs left over.

How many eggs did Takeru buy and how many soufflés did he bake?

Answer:

Takeru bought  72 eggs and made 18 souffles

Step-by-step explanation:

Given:

Number of eggs per souffle   = 3

Number of left over egg  = 18

Number of eggs  bought  = 4 times as he baked soufflés

To find:

Number of many eggs did Takeru buy = ?

Number of souffles baked = ?

Solution:

Let x  be number of souffles Takeru  

Let y be number  eggs

Then, the question says that he bought 4 times as many eggs as he baked souffles.

so the number of eggs  

y = 4x----------------------------(1)

After making x souffles he is left with 18 eggs, and for making x souffle he uses 3x eggs ,so

Total eggs - eggs used to make x souffle = 18

y - 3x  =18-------------------(2)

substituting (1) in (2)

4x - 3x  = 18

x = 18--------------------------(3)

Substituting (3) in(1)

y = 4(18)

y = 72

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Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
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Answer:

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The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

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Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

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S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

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Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

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Simplifying, we have

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Factoring we have,

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