Answer:
The volume of water in the fish tank is 4.5 cubic feet
see the explanation
Step-by-step explanation:
<u><em>The complete question is</em></u>
Explain how you found the volume of water in the fish tank if it was only 1/2 full with water. Show your work and solution. Don't forget your UNITS!
You have a fish tank with the following dimensions:
Height: 3 feet
Width: 1.5 feet
Length: 2 feet
step 1
Find the volume of the fish tank
The volume of a rectangular prism ( fish tank) is equal to
substitute the given values
step 2
Find the volume of water in the fish tank
Remember that
The fish tank it was only one and a half full with water
so
Multiply the volume of the fish tank by one and a half to obtain the volume of water
1. Unless you have the total students, it would be D, because we don't know how many total students there are, so we don't know how many students 100% would be.
2. E. There are only 7% of the students who major in a medical area. So say out of 100 students, 7% of that would be 7 people, and 19% would be 19 people, and so on. So therefore, the least people are majoring in a medical field.
Answer:
y greater than or equal to 14
Step-by-step explanation:
Given the inequality:
We solve it by isolating the variable y on one side. That is, in our case we add 27 to both sides and get:
Answer: 2, 2, 13, 13
Step-by-step explanation: Prime number are numbers that can divide without remainder, This means that 676 is divisible by 2, 2, 13, 13, numbers.
Answer:
![\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%265%5C%5C1%261%261%5C%5C4%266%265%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx1%5C%5Cx2%5C%5Cx3%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C6%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's find the answer.
Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.
Equations:
Eq. 1 : x1 + 2x2 + 5x3 = 5
Eq. 2 : x1 + x2 + x3 = 6
E1. 3 : 4x1 + 6x2 + 5x3 = 7
Coefficients for x1 ; x2 ; x3
From eq. 1 : 1 ; 2 ; 5
From eq. 2 : 1 ; 1 ; 1
From eq. 3 : 4 ; 6 ; 5
So matrix A is:
![\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%265%5C%5C1%261%261%5C%5C4%266%265%5Cend%7Barray%7D%5Cright%5D)
And the vector of vriables (X) is:
![\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx1%5C%5Cx2%5C%5Cx3%5Cend%7Barray%7D%5Cright%5D)
Now we can find the resulting vector (B) using the 'resulting values' from each equation:
![\left[\begin{array}{ccc}5\\6\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C6%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
In conclusion, AX=B is:
