Answer:
20/18
Step-by-step explanation:
<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)
The equation of the parabola whose focus is at (7, 0) and directrix at y = -7 is
(x-7)^2 = 14(y + 7/2)
Hope this helps
Answer:
D. (2, 0)
Step-by-step explanation:
The solutions are the two points of intersection of the graphs:
(-2, -4) and (2, 0)
The latter of these corresponds to choice D, the one you have marked.
Answer:
The answers to the first three problems are shown in the figure attached
Fourth problem answer: 3.5 cm
Step-by-step explanation:
In problem 1, move the given triangle ABC four units to the right and 2 units down as what the displacement vector "v" indicates.
You may do such by translating each vertex of the triangle ABC such number of units one at a time and then joining the vertices.
In problem 2 the requested translation vector "v" indicates 4 units to the right and 1 unit up. Do such translation for each vertex of the triangle as suggested before.
In problem 3 the requested translation "v" asks for 2 units to the left and 3 up.
Do the translation of each vertex following these instructions.
Problem 4: use a ruler and notice that the length of the vector xy given has exactly the same length as the distance between the vertices A in one triangle, and A' in the other. The same is true for the distance between vertex B and B' in the other triangle, and for the distance between C and C'.