Step-by-step explanation:
The opposite side is the side of the triangle facing the given angle. The adjacent side is the side that the given angle and the right angle lies on. The hypotenuse side is the side facing the right angle. (The hypotenuse side usually looks like a slanted line. Do note that this is not true if your adjacent and hypotenuse side is not horizontal and vertical respectively on the plane of your paper.)
I'll explain a bit more below using the some of the questions.
Q1) The given angle here is 27°.
X is facing the given angle hence it is the opposite side.
The side that is 10 units long is the adjacent side as 27° and the right angle sits on it.
tanθ= opp/adj
tan27°= x/ 10
x= 10(tan 27°)
x= 5.1 units (nearest tenth)
Q3) x is the adjacent side, while the side that is 7 units long is the hypotenuse side.
cosθ= adj/hyp
cos39°= x/7
x= 7(cos39°)
x= 5.4 units (nearest tenth)
Q4) x is the hypotenuse and the opposite side is 8 units long.
sinθ= opp/hyp
sin46°= 8/x
x(sin46°)= 8
x= 8/ sin46°
x= 11.1 units (nearest tenth)
Q5) x is facing the given angle, hence it is the opposite side. The adjacent side is given here, which is 6 units long.
tanθ= opp/adj
tan23°= x/6
x= 6(tan 23°)
x= 2.5 units (nearest tenth)
Feel free to ask if you still do not understand any concepts :)
sinθ= opp/hyp
cosθ= adj/hyp
tanθ= opp/adj
Answer:
A nitrogen level of 1 gives the best yield.
Step-by-step explanation:
We are given the following:
Yield Y of an agricultural crop as a function of the nitrogen level N in the soil
First, we differentiate Y(N) with respect to N, to get,
Equating the first derivative to zero, we get,
Solving, we get,
Again differentiation Y(N), with respect to N, we get,
At N = 1
Thus, by double derivative test, the maximum value of Y(N) occurs at N = 1.
Thus, largest yield of crop is given by:
Y(1) =
Answer: Okay so im not entirely sure if you need this still or if i am right but this is what ive got.
a) the chance of landing on the letter D is 1/3 because there are 4 sections labeled D and total there is 12. Therefore, 4 is 1/3 of 12 giving me the answer.
b) the chance of landing on the letter A is 1/6 because there are only 2 sections labeled A and total there is 12. Since that is the case, 2 is 1/6 of 12.
c) the chance of landing on the letter A and D is easy to find. You would just add the chances of getting the letter A and the letter D and there is your answer. 1/3 + 1/6= 3/6 or 1/2.
d) the experimental probability of the spinner landing on B is a 6/20 chance because the number of trials are 20, the denominator, and 6 is the event, numerator, which gives 6/20 or 3/10 simplified.
e) the experimental probability of the spinner landing on E is a 2/20 chance because the number of trials is 20, which is the denominator, and 2 is the event, numerator which gives 2/20 or 1/10 simplified
