Answer:
Step-by-step explanation:
<h3>A.</h3>
The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>
The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
First you subtract 25 from 5 which equals 20 then you multipliy 4 to 20 and you get 80...so 80 is your solution.
<span>The missing angle measure in triangle ABC is 55°.
The measure of angle BAC in triangle ABC is equal to the measure of angle
EDF in triangle DEF.
The measure of angle ABC in triangle ABC is equal to the measure of </span><span>angle EFD in triangle DEF.
Triangles ABC and DEF are similar by the angle-angle criterion.
True </span>
2(x+2) > x+5
2x+4 > x+5
2x+4-x > x+5-x
x+4 > 5
x+4-4 > 5-4
x > 1
Combine like terms
9r+r=10r^2
7b+b=8b^2
10+10r^2+8b^2+4n