<u>ANSWER</u>
1. 
2. 
<u>QUESTION 1</u>
The first sentence is
.
Recall that;

We simplify the left hand side by applying this property to get;
.
.
We now rewrite the right hand side too in an index form to obtain;

We now equate the exponents to get;
.

.
<u>QUESTION 2</u>
The second sentence is 
We simplify the left hand side first to get;


We now rewrite the left hand side too in index form to obtain;

We equate the exponents to get;

This implies that;

or

Answer:
the length is 4 ft longer than the height
Step-by-step explanation:
Answer:
- vertex (3, -1)
- y-intercept: (0, 8)
- x-intercepts: (2, 0), (4, 0)
Step-by-step explanation:
You are being asked to read the coordinates of several points from the graph. Each set of coordinates is an (x, y) pair, where the first coordinate is the horizontal distance to the right of the y-axis, and the second coordinate is the vertical distance above the x-axis. The distances are measured according to the scales marked on the x- and y-axes.
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<h3>Vertex</h3>
The vertex is the low point of the graph. The graph is horizontally symmetrical about this point. On this graph, the vertex is (3, -1).
<h3>Y-intercept</h3>
The y-intercept is the point where the graph crosses the y-axis. On this graph, the y-intercept is (0, 8).
<h3>X-intercepts</h3>
The x-intercepts are the points where the graph crosses the x-axis. You will notice they are symmetrically located about the vertex. On this graph, the x-intercepts are (2, 0) and (4, 0).
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<em>Additional comment</em>
The reminder that these are "points" is to ensure that you write both coordinates as an ordered pair. We know the x-intercepts have a y-value of zero, for example, so there is a tendency to identify them simply as x=2 and x=4. This problem statement is telling you to write them as ordered pairs.
Answer:
(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)
(b) The initial condition t > 0 will not make much of a difference.
Step-by-step explanation:
Given the differential equation
dx/dt= −k(x − A); t > 0, A = A_0Coswt
(a) To solve the differential equation, first separate the variables.
dx/(x - A) = -kdt
Integrating both sides, we have
ln(x - A) = -kt + c
x - A = Ce^(-kt) (Where C = ce^(-kt))
x = A + Ce^(-kx)
Now, we put A = A_0Coswt
x = A_0Coswt + Ce^(-kx) (Where C is constant.)
And we have the solution.
(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).
It is not any different from when t < 0.