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1 year ago

Here is a polygon. draw a scaled copy of the polycon with scale factor 3

Mathematics

1 answer:

Ulleksa [173]1 year ago

4 0

The scaled copy of the polygon is added as an attachment

<h3>How to draw the scaled copy?</h3>

The complete question is added as an attachment

The coordinates of the polygon are

A = (-7, 6)

B = (-10, 8)

C = (-10, 10)

D = (-6, 10)

The scale factor is 3.

So, the rule of dilation is

(x, y) = (3x, 3y)

Using the above rule, we have:

A' = (-21, 18)

B' = (-30, 24)

C' = (-30, 30)

D' = (-18, 30)

See attachment for the scaled copy of the polygon

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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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2 years ago

Molly painted a line around the entire perimeter of the basketball court. The length of the court was 32 meters and the width wa

xz_007 [3.2K]

The answer is 98 meters :)

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2 years ago

-18,-13,-8,-3,....<br><br> Find the above sequential formula

zhuklara [117]

The first term (a) is - 18

You add 5 to get to the next term. Or you can solve it by taking any 2 consecutive terms and find their difference.

Formula

d = t4- t3

Givens

t4 = - 3

t3 = - 8

Solution 1

d = t4 - t3 Substitute

d = -3 - ( - 8) Remove the brackets

d = -3 + 8 Combine

d = 5 Difference

Remark

Find the general formula

tn = - a + (n - 1)d Substitute

So term 20 = Example

t20 = -18 + (20 - 1)*5 Combine the inside of the brackets. Remove the brackets

t20 = - 18 + 19*5 Combine 19 and 5

t20 = -18 + 95 "Subtract"

t20 = 77 Answer

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2 years ago

which of the following is the algebraic expression that best describes the sequence 3, 9, 27, 81, 243,...?

Anton [14]

${3}^{n}$

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2 years ago

A car can be rented for $75 per week plus $0.35 per mile. How many miles can be driven if you have at most $110 to spend for wee

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2 years ago