Answer:
Hence proved △ABE∼△CBF.
Step-by-step explanation:
Given,
ABCD is a parallelogram.
BF ⊥ CD and
BE ⊥ AD
To Prove : △ABE∼△CBF
We have drawn the diagram for your reference.
Proof:
Since ABCD is a parallelogram,
So according to the property of parallelogram opposite angles are equal in measure.
⇒1
And given that BF ⊥ CD and BE ⊥ AD.
So we can say that;
⇒2
Now In △ABE and △CBF
∠A = ∠C (from 1)
∠E = ∠F (from 2)
So by A.A. similarity postulate;
△ABE∼△CBF
Answer:
35
Step-by-step explanation:
write 5 in N's place
5^2+2×5×1
25+10
35
W^B = W×W×W×W... (#B times)
Something along those lines.
146. They are asking for the angle XY, the blue line.
For instance, imagine it is 90 deg, instead of 73, it would cut the circle in two, and XY would be 180 deg. Imagine it would be 45 degrees, it would leave a quadrant, and that's 90 deg.
So the angle * 2 (they are different angles)
I think 'TheBestBrain' thought they were asking for the supplementary angle, but I think it is the arc length angle (blue line)
