Ask question

Ask question

All categories

3 years ago

10

D-2.8 divided by 0.2 = -14 solve the equation

2 answers:

yarga [219]3 years ago

8 0

Answer:

The value of d is 0.

Step-by-step explanation:

Consider the provided statement.

d-2.8 divided by 0.2 = -14

This can be written as:

$\frac{d-2.8}{0.2}=-14$

Multiply both the side by 0.2

$d-2.8=-14\times 0.2$

$d-2.8=-2.8$

Add 2.8 to the both sides.

$d-2.8+2.8=-2.8+2.8$

$d=0$

Hence, the value of d is 0.

ohaa [14]3 years ago

7 0

(d-2.8)/0.2=-14
d-2.8=-14*0.2
d-2.8=-2.8
d=-2.8+2.8
d=0

You might be interested in

Is this proportional?

nikklg [1K]

Yes it is !! also I LOVE YOUR PFP

4 0

3 years ago

Read 2 more answers

105. Find the inverse g for each function f.<br> b. f(x) = x+ 3/x-2

mestny [16]

Hope this helps. I switch the x and y so its easier to solve.

4 0

4 years ago

Problems 2.21, 2.22, 2.23

RoseWind [281]

Statements can be proved by contrapositive, contradiction or by induction.

<em>2.21 and 2.23 are proved by contrapositive</em>
<em>2.22 is proved by induction</em>

<u />

<u />

<u>2.21: If </u> $n^3$ <u> is even, then n is even (By contrapositive)</u>

The contrapositive of the above statement is that:

<em>If n is odd, then </em> $n^3$ <em> is odd</em>

Represent the value of n as:

$n = 2k + 1$ , where $k \ge 0$

Take the cube of both sides

$n^3 = (2k + 1)^3$

Expand

$n^3 = 8k^3 + 6k^2 + 6k + 1$

Group

$n^3 =[ 8k^3 + 6k^2 + 6k] + 1$

Factor out 2

$n^3 =2[4k^3 + 3k^2 + 3k] + 1$

Assume w is an integer; where:

$w =4k^3 + 3k^2 + 3k$

So, we have:

$n^3 =2w + 1$

The constant term (i.e. 1) means that $n^3$ is odd.

Hence, the statement has been proved by contrapositive.

<em>i.e. If n is odd, then </em> $n^3$ <em> is odd</em>

<u />

<u>2.22 </u> $3n + 4$ <u> is even, if and only if n is even</u>

We have: $3n + 4$ <u />

<u />

Assume that: $n = 2k + 2$ for $k \ge 0$

So, we have:

$3n + 4 = 3(2k + 2) + 4$

Open bracket

$3n + 4 = 6k + 6 + 4$

$3n + 4 = 6k + 10$

Factorize

$3n + 4 = 2(3k + 5)$

The factor of 2 means that $3n + 4$ is even.

<em>Hence, </em> $3n + 4$ <em> is even, if and only if n is even </em>

<em />

<u />

<u>2.22: </u> $s \ne -1$ <u> and </u> $t \ne -1$ <u>, then </u> $s + t + st \ne -1$ <u />

To do this, we prove by contrapositive.

The contrapositive of the above statement is:

If $s = -1$ and $t=-1$ , then $s + t + st = -1$

We have:

$s + t + st = -1$

Substitute the values of s and t in: $s + t + st = -1$

$-1 -1 -1 \times -1 = -1$

$-1 -1 + 1 = -1$

$-1 = -1$

Hence, by contrapositive:

If $s = -1$ and $t=-1$ , then $s + t + st = -1$

Read more about proofs at:

brainly.com/question/19643658

7 0

3 years ago

Solve with elimination:<br> -2x - 4y = 8<br> -6x +24 = 12y

Elanso [62]

Ohh, Elimination Im doing that XD So its

Anwser - No Solution

8 0

3 years ago

Write an equation in slope-intercept form of the line that passes through the given points

Elis [28]

$y= -\frac{3x}{2} +1$

3 0

3 years ago