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igor_vitrenko [27]
3 years ago
15

I need help bad!!!!!!! Question: Angle ABC and angle DEF are supplementary. If

Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

Angle ABC and angle DEF are supplementary if and only if they add up to 180 degrees

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True or false pls help!! I WILL MARK BRAINLIST
Ilya [14]

Answer:

True

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will
lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

V(t) = 14651(0.81)^{t}

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

V(t) = 14651(0.81)^{t}

(0.81)^t = \frac{V(t)}{14651}

\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}

t\log{(0.81)} = \log{(\frac{V(t)}{14651})}

t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}

(a) $8000

V(t) = 8000

t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7

The car will be worth $1000 after 12.7 years.

5 0
2 years ago
What's the area of a rectangle measuring 13in × 12in
slamgirl [31]
Hey there
Your answer is 156 hope it helps:)
- Maddie
5 0
3 years ago
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A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have thr
kati45 [8]

Answer:

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

23\cdot 23\cdot 23\cdot 6\cdot 6=438012

Therefore, we can choose coupon codes in 438,012 ways.

3 0
3 years ago
Use the stem and leaf plot shown to answer the following question.
DENIUS [597]
16, 18, 23, 25, 26, 34, 37, 37, 40, 41, 46

37 is the upper quartile value
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