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Answer:
- modulus: 3√2
- argument: -3π/4 (or 5π/4)
Step-by-step explanation:
The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).
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<h3>rectangular form</h3>The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:
The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:
modulus = √((-3)² +(-3)²) = 3√2
The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.
arg = arctan(-3/-3) = -3π/4 or 5π/4 . . . . radians
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modulus∠argument = (3√2)∠(-3π/4)
We have equation:
When
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are the solutions, from <span>Vieta's formulas we know that:
and:
So:
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When
and:
So:
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