You need to work about 12.5 hours because from your gas station job, since you work 30 hours every week, times that by 8.75$ which equals 262.5$ at the end of the week, so subtract 262.5 from 400 which is 137.5, then you need to dived that by 11 since its $ per hour, after doing that you get 12.5 hours, so you would have to work 12.5 hours at your landscaper job
The zero product property tells us that if the product of two or more factors is zero, then each one of these factors CAN be zero.
For more context let's look at the first equation in the problem that we can apply this to:

Through zero property we know that the factor

can be equal to zero as well as

. This is because, even if only one of them is zero, the product will immediately be zero.
The zero product property is best applied to
factorable quadratic equations in this case.
Another factorable equation would be

since we can factor out

and end up with

. Now we'll end up with two factors,

and

, which we can apply the zero product property to.
The rest of the options are not factorable thus the zero product property won't apply to them.
Answer: Add the equations to eliminate k
Step-by-step explanation:
Adding the equations, you get 2b=18, which you can solve for b. Afterward, you can substitute this value of b back into either equation to solve for k.
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
An expression for the cost will be 50+100n, where n is the number of cavities.