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4 years ago

9+3x2 10 points please

Mathematics

1 answer:

Hitman42 [59]4 years ago

7 0

answer is 24

9+3=12

12×2=24

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2.6 more than the quotient of h and 3 is w

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So, "2.5 more than the quotient of h and 3 is w" becomes 2.5 + h/3 = w.

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3/5

Step-by-step explanation:

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3 years ago

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Triangle ABC is shown below.

Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

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$AB=AC\\\\2x=3x-7$

Simplify the equation, solving for x. Add 7 to both sides:

$2x+7=3x-7+7\\\\2x+7=3x$

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$2x-2x+7=3x-2x\\\\7=x$

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$AC=3(7)-7$

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$AC=21-7$

Subtract:

$AC=14$

Therefore, the length of the line segment AC is 14.

:Done

8 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

4 years ago

Matt invests $1,669 in a saving account with a fixed annual interest rate of 2% compounded 12 times per year. How long will it t

vesna_86 [32]

Answer:

It will take 4.84 years

Step-by-step explanation:

The initial amount that Matt invested was $1669. It means that principal is

P = 1669

It was compounded 12 times per year. So

n = 12

The rate at which the principal was compounded is 2%. So

r = 2/100 = 0.02

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years.

A = 1,844.38

Therefore

1,844.38 = 1669(1+0.02/12)^(12×t)

1,844.38/1669 = (1.0017)^(12t)

1.1051 = (1.0017)^(12t)

Taking log to base 10 of both sides, it becomes

Log 1.1051 = log 1.0017^(12t)

Log 1.1051 = 12tlog 1.0017

0.043 = 0.00074 × 12t

0.043 = 0.00888t

t = 0.043/0.00888

t = 4.84 years

6 0

3 years ago