You are sailing from your lakeshore cabin to a marina 60º north of east and 0.5 miles across the lake. On your return trip, you
decide to sail directly south and then west to get back to your cabin. How far would you now have to sail?
a.
0.68 miles
b.
0.43 miles
c.
0.25 miles
d.
0.5 miles
For this case what we should observe is that we have a rectangle triangle where we know: Angle. Hypotenuse. We want to know: opposite cateto Adjacent cateto We apply the following trigonometric formulas: Sine (x) = C.O / h Cosine (x) = C.A / h Where, x: angle C.O: opposite leg C.A: adjacent leg h: hypotenuse Substituting values: Sine (60) = C.O / 0.5 Cosine (60) = C.A / 0.5 Clearing: C.O = 0.5 * Sine (60) = 0.43 C.A = 0.5 * Cosine (60) = 0.25 Then, adding both sides we have: C.O + C.A = 0.43 + 0.25 = 0.68 miles Answer: you now woluld have to sail: a. 0.68 miles
The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.