3 years ago

Is this 61?????Is it right

1 answer:

6 0

Point Q is -6 from point R
Point R is 7 from point T
Point T is -3 from point S

Area = 1/2(6+9)(7)

Area = 1/2 (15)(7)
Area = 52.5 square units

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kirill115 [55]

I believe it is (-3,-1)

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3 years ago

timurjin [86]

What do you need help with? Please include description or, add a photo of the problem so others can see whether they can help out or not.

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3 years ago

timurjin [86]

Y = yo + Vot - (gt^2)/2

0 = 0 + 31t - 4.9 t^2

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Answer: option A.

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Vadim26 [7]

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3 years ago

Andru [333]

Answer:

Perimeter of the Quadrilateral=20.78

Step-by-step explanation:

Perimeter of the Quadrilateral= AB+BC+CD+AD

Finding the sides of the quadrilateral using the Distance formula:

A(-3,0), B(2,4), C(3,1) and D(-4,-3)

$AB=\sqrt{(2-(-3))^2+(4-0)^2}\\\\ =\sqrt{(2+3)^2+4^2}\\\\ =\sqrt{5^2+4^2} \\\\=\sqrt{25+16}\\\\ =\sqrt{41}\\$

$=6.40$

BC=

$\sqrt{(3-2)^2+(1-4)^2} \\\\=\sqrt{1^2+(-3)^2} \\\\=\sqrt{1+9}\\\\ =\sqrt{10}$

$=3.16$

$CD=\sqrt{(-4-3)^2+(-3-1)^2} \\\\=\sqrt{(-7)^2+(-4)^2} \\\\=\sqrt{49+16}\\\\=\sqrt{65}\\\\ =8.06$

$AD=\sqrt{(-4-(-3))^2+(-3-0)^2} \\\\=\sqrt{(-4+3)^2+(-3)^2} \\\\=\sqrt{(-1)^2+(-3)^2} \\\\=\sqrt{1+9}\\\\=\sqrt{10} \\\\ =3.16$

Perimeter of the quadrilateral= AB+BC+CD+AD

=6.40+3.16+8.06+3.16

=20.78

6 0

3 years ago