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padilas [110]
4 years ago
14

What is the area of 'P'.​

Mathematics
1 answer:
AVprozaik [17]4 years ago
6 0

Answer:

12 square centimetres

Step-by-step explanation:

6*2=12

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What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1?
JulsSmile [24]
Alright,
directix is y=something so it opens down or up

we use
(x-h)²=4p(y-k)
the vertex is (h,k)
and p is distance from focus to vertex
if focus is above directix, p is positive
if focus is below directix, p is negative

so we gts

focus=(1,1)
directix is y=-1
1>-1
focus is above

oh, vertex is in middle of focus and directix
so
beteeen (1,1) and y=-1 is, hmm
that is a distance of 2 vertically
2/2=1
1 down from (1,1) is (1,0)
vertex is (1,0)
p=1

so
(x-1)²=4(1)(y-0)
solving for y to get into f(x)=something form
(x-1)²=4y
y=1/4(x-1)²
f(x)=1/4(x-1)²

4th option
6 0
3 years ago
Help me out important!!!!!!!
Oliga [24]

Answer:

This might help:

3 0
3 years ago
IM GIVING BRAINLIEST!!PLEASE HELP!!I PROMISE!!
Lilit [14]

Answer:

i think it's b sorry if it's wrong

Step-by-step explanation:

3 0
3 years ago
What is and how do you do it?<br><br> H(x) = 4x-2<br> G(x) = x^2 -5<br><br> Find h(x) + g(x)
sineoko [7]

h(x)=4x-2\\\\(x)=x^2-5\\\\h(x)+g(x)=(4x-2)+(x^2-5)=x^2+4x+(-2-5)\\\\=x^2+4x-7

6 0
3 years ago
How can i do this please help me
Aleksandr-060686 [28]

The tangent of an angle is the ratio of the opposite side to the adjacent side.

... tan(45°) = (height above eye level)/(20 m)

... height above eye level = (20 m)·tan(45°) = (20 m)·1 = 20 m

_____

Eye level is 1.7 m above ground, so the height of the flagpole above ground is

... height of pole = height above eye level + height of eye level

... height of pole = 20 m + 1.7 m = 21.7 m

7 0
3 years ago
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