Triangle ACB and triangle ABD share one side AB. This means they have one side that is congruent; side AB
Angle ABD = Angle ABC
Angle BAC = Angle BAD
The pair of angles that are equal lie on the side AB
Hence, triangle ABC and triangle ABD are congruent by Angle-Side-Angle (ASA)
Answer: Second option
Answer:
y = 6/5
Step-by-step explanation:
3x - 5y = -3
Let x =1
3(1) - 5y = -3
3-5y = -3
Subtract 3 from each side
3-3-5y = -3-3
-5y = -6
Divide each side by -5
-5y/-5 = -6/-5
y = 6/5
6x2 = 12
12 / 3 = 4 <span>6=6/1 so you do the numerators x the denominators which is 6x2/1x3=12/3 then simplify and make into a mixed number so final answer is 4</span>
Median: 3
mode: 3
range: 9
interquartile range: 2
the outliers are 9 and 5. there is a cluster between 2 and 3.
Answer: No one ever answers
Step-by-step explanation: