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Lana71 [14]
3 years ago
13

What is the solution to the following system of equations? x+y=5

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

(3,2)

Step-by-step explanation:

Let's solve this via elimination method:

\begin{cases} x+y=5\\x-y=1\end{cases}

By subtracting equation 2 from equation one we obtain:

\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1.  Let y=2 and so:

x+y=5\\\\x+2=5\\x=5-2\\\\x=3

Therefore the solution for the system of equations is:

x=3 and y = 2 as an ordered pair we have (3,2)

You might be interested in
Chris
Rainbow [258]

Answer:

meat = $2.40

vegetables = $ 2.40

fruit = $2.40 + X

= 2.40 ÷ 2

= 1.2

therefore 2.40 + 1.2

=$3.6 (For fruits )

= $3.6 + $2.40 + $2.40

= $ 8.4

Hope this helps .Plzz mark me brainliest

7 0
3 years ago
Which of the following expressions are equivalent to 6 + (-4) - 5
Mila [183]

Answer:

B and C

Step-by-step explanation:

All you need to do is find the answer for all of them and see which ones match

Original:

6 + (-4) - 5

6 - 4 - 5

2 - 5

<u><em>-3</em></u>

This is the answer for the original expression, now we need to see which one is the correct match....

A. -(-6 + 4 ) - 5

2 negatives being subtracted gives you a positive

6 + 4 - 5

10 - 5

5

Incorrect, so now we know its not A

B. 6 - 4 - ( -5)

Again 2 negatives give you a positive

6 - 4 + (5)

6 - 9

-3

Correct, so now we know its B

C. 6 - (4 + 5)

PEMDAS so do the parenthesis first

6 - 9

-3

Correct, so now we it's C.

D. 6 + 4 - 56

10 - 56

-46

Incorrect, so now we know its not D

E. -(-6) + (-4) - (-5)

Again, 2 negatives equal a positive

6 - 4 + 5

2 + 5

7

Incorrect so now we know its not E

The correct answer is C

Hope this helped!

Have a supercalifragilisticexpialidocious day!

6 0
3 years ago
3. f(-4) – 3.g(-2) =
Finger [1]
I got:
-2(2f-3g)

explanation:
used communicative property
6 0
3 years ago
What is the difference of the polynomials?<br><br> (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)
ANEK [815]
For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= <span><span><span><span><span>−<span><span>6x4</span>y</span></span>−<span><span>2x3</span>y2</span></span>+<span><span>9x2</span>y3</span></span>−<span>3xy4</span></span>+y5</span> 

I hope this helps
4 0
3 years ago
Read 2 more answers
A detergent company periodically tests its products for variations in the fill weight. To do this, the company uses x-bar and R
maw [93]

Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar      R

5.8        0.42

6.1         0.38

16.02    0.08

15.95    0.15

16.12     0.42

6.18      0.23

5.87     0.36

16.2      0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

LCL=10.9361

8 0
3 years ago
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