You don't need the apothem if the side length is known, the area can be expressed as:
A(n,s)=ns^2/(4tan(180/n)), n=number of sides and s=side length so
A(7,28)=(7*28^2)/(4tan(180/7))
A≈2848.987 ft^2
A≈2849 ft^2 (to the nearest tenth of a square foot)
Answer:
B.)The volume of the triangular prism is not equal to the volume of the cylinder.
Step-by-step explanation:
Let A be the cross-sectional area of both congruent right triangular prism and right cylinder.
Since the prism has height 2 units, its volume V₁ = 2A.
Since the cylinder has height 6 units, its volume is V₂ = 6A
Dividing V₁/V₂ = 2A/6A =1/3
V₁ = V₂/3.
The volume of the prism is one-third the volume of the cylinder.
So, since the volume of the prism is neither double nor half of the volume of the cylinder nor is it equal to the volume of the cylinder, B is the correct answer.
So, the volume of the triangular prism is not equal to the volume of the cylinder.
The answer is D. You can't make an equation out of this!
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The number (x) that is (=) 10 less than (-) 6
x = 6 - 10 Subtract
x = -4
<h2>The height of the rocket increases for some time and then decreases for some time.</h2>
The height from the ground increases from 4 to 26, then decreases from 26 to 0.
Why the others are wrong.
A. The height of the rocket changes at a constant rate for the entire time.
The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.
C. The height of the rocket remains constant for some time.
The graph is a curve. This means the rate is not constant. If it were constant, the graph would be linear - a straight line.
D. The height of the rocket decreases for some time and then increases for some time.
This implies the graph decreases first then increases. However, the rocket will increase, then decrease.