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Lana71 [14]
3 years ago
13

What is the solution to the following system of equations? x+y=5

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

(3,2)

Step-by-step explanation:

Let's solve this via elimination method:

\begin{cases} x+y=5\\x-y=1\end{cases}

By subtracting equation 2 from equation one we obtain:

\begin{cases} x+y=5\\-(x-y=1)\end{cases}\\\\0x+2y=4\\\\y=2

Next we can use any equation either 1 or 2 to determine what x is, I'll use equation 1.  Let y=2 and so:

x+y=5\\\\x+2=5\\x=5-2\\\\x=3

Therefore the solution for the system of equations is:

x=3 and y = 2 as an ordered pair we have (3,2)

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Suppose y varies directly as x, and y=14 when x=4. What is the value of y when x=9
Katena32 [7]

Given :-

  • y varies directly as x, and y=14 when x=4.

To Find :-

  • the value of y when x=9 .

Solution :-

<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>,</u>

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<u>When</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u> </u><u>,</u>

  • 14 = k(4)
  • k = 14/4
  • k = 7/2

<u>W</u><u>h</u><u>e</u><u>n</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>,</u>

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3 years ago
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ryzh [129]

Answer:

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Step-by-step explanation:

3x^2 + 6x -9

All the terms in this polynomial are divisible by 3. Factor 3 out of this polynomial:

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Now, factor inside the parentheses by grouping:

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= 3(x(x -1)+3(x -1))\\= 3(x+3)(x -1)

Therefore, the final factored polynomial is 3(x+3)(x -1).

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