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iogann1982 [59]

3 years ago

5

The answers are either 1. centroid 2. orthocenter 3. incenter 4. circumcenter

1 answer:

slamgirl [31]3 years ago

4 0

Answer Centroid!

Step-by-step explanation: A centroid of a triangle is the point where the three medians of the triangle meet.

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CORRECT GETS BRAINLIEST A pizzeria delivered p pizzas on Thursday. On Friday, it delivered 3 more

Alex73 [517]

Answer:

(p×2)+3

Step-by-step explanation:

I'm not too sure, I've only just started practicing this stuff?

8 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

How do you solve -h/3 - 4 = 13

Phantasy [73]

Answer is -h = -51 (download photomath)

8 0

3 years ago

Which phrase best describes the translation from the graph y = (x + 2)2 to the graph of y = x2 + 3?

Mashutka [201]

1. Consider the transformation that maps the graph of the function $y=(x+2)^2$ into the graph of the function $y=x^2.$ This transmormation has a rule:

(x,y)→(x+2,y)

that is translation 2 units to the right.

2. Consider the transformation that maps the graph of the function $y=x^2$ into the graph of the function $y=x^2+3.$ This transformation has a rule:

(x,y)→(x,y+3)

that is translation 3 units up.

Answer: correct choice is C.

7 0

3 years ago

Read 2 more answers

Write an equation that could be used to find the value of x using the interior angles of ∆BDC, then solve it.

Alecsey [184]

9514 1404 393

Answer:

x = 16

Step-by-step explanation:

Either or both of the right triangles can be used to find x. Or, triangle ABC could be used. All numbers are assumed to be degrees.

<u>Using ∆ABD</u>

55 +90 +2x+3 = 180

2x = 32 . . . . . . subtract 148

x = 16

<u>Using ∆BCD</u>

50 +90 +2x+8 = 180

2x = 32 . . . . . . subtract 148

x = 16

<u>Using ∆ABC</u>

55 +(2x +3) +50 +(2x +8) = 180

4x = 64 . . . . . . . subtract 116

x = 16

6 0

3 years ago