So if you solve for n 4n^2+3=7n make into trinomial subtract 7n from both sides 4n^2-7n+3=0 if we can factor this, then we can asume that the factors are equal to zero becase if xy=0 then assume x and/or y=0 so
to factor an equation in ax^2+bx+c where a is greater than 1 then b=t+z a times c=t times z to factor 4n^2-7n+3 you do 4 times 3=12 what 2 numbers multiply to get 12 and add to get -7 the numbers are -3 and -4 so split up the -7 4n^2-4n-3n+3 group (4n^2-4n)+(-3n+3) undistribute (4n)(n-1)+(-3)(n-1) reverse distributive property ab+ac=a(b+c) (4n-3)(n-1)=0 set each to zero 4n-3=0 add 3 to both sides 4n=3 divide both sides by 4 n=3/4
