To solve this, we have to find the volume of the cylinder first. The formula to be used is

Given:V= ?r= 6cmh= 10cm
Solution:

V= (3.14)(6cm)

x 10cmV= (3.14)(

) x 10cmV= (

) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Answer:
Es 60
Step-by-step explanation:
Answer:
you stupid and dumb person
R^2/2(pi/180*D-sin(D)) is the formula so 6^2/2(pi/180*120-sin(120)) is the problem which comes to about 22cm^2
Answer:
5 m
Step-by-step explanation:
A model car is made to a scale of 1:50 (model: real).
If the model has a length of 10 cm, calculate the length of the real car (answer in meters).
We have a scale of :
model: real = 1:50
The model has a length of 10cm
Hence:
1 cm = 50 cm
10 cm = x cm
Cross Multiply
x cm × 1cm = 10 cm × 50 cm
x cm = 10 cm × 50 cm/1cm
x cm = 500 cm
The length of the real car is 500cm
Converting the length of the real car to meters
100cm = 1 m
500 cm = x m
Cross Multiply
100cm × x m = 500 cm × 1 m
x m = 500 cm × 1 m/100 cm
x m = 5 m
The Length of the real car in meters is 5m