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Anna [14]
3 years ago
5

An object is launched straight upward from ground level with an initial velocity of 32 feet per second. The formula h=32t - 16t

^ 2 gives its height, h, in feet after t seconds. At what time does the object hit the ground?
A. t=16
B. t=2
C. t=1
D. t=0
Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer: B. t=2

Step-by-step explanation:

If we implement t=2 into the function h=32(2)-16(2)^2 we get the height of 0 (Ground level).

Solve for h by simplifying both sides of the equation, then isolating the variable.

Hope this helps! :)

Angelina_Jolie [31]3 years ago
3 0
I think it’s D hope that helped
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\large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N : }}

\large{ \tt{✽ \: m \: \angle \: RQP =   m \: \angle \:  RQH + m \:  \angle \: HQP}}

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▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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