Question

An object is launched straight upward from ground level with an initial velocity of 32 feet per second. The formula h=32t - 16t ^ 2 gives its height, h, in feet after t seconds. At what time does the object hit the ground?
A. t=16
B. t=2
C. t=1
D. t=0

Answer 1

Answer: B. t=2

Step-by-step explanation:

If we implement t=2 into the function h=32(2)-16(2)^2 we get the height of 0 (Ground level).

Solve for h by simplifying both sides of the equation, then isolating the variable.

Hope this helps! :)

Answer 2

I think it’s D hope that helped