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Sunny_sXe [5.5K]
3 years ago
11

Please answer the question and please answer correctly... I really need help

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

The treatment decays by half each week.

Step-by-step explanation:

The decay function is given by:

y=a(1-r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = decay rate

<em>t </em>= time

The decay function for one medications to treat dogs for fleas is:

F(x)=4\cdot (\frac{1}{2})^{w}

Here the decay rate is:

1-r=\frac{1}{2}\\\\r=1-\frac{1}{2}\\\\r=\frac{1}{2}

The treatment decays by half each week.

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Find the product of 4cis (pi/4) times 5cis (pi/6) in polar form.
KengaRu [80]

We have the following expression

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})

This is equivalent to

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=(4\times5)cis(\frac{\pi}{4}+\frac{\pi}{6})

Since

\frac{\pi}{4}+\frac{\pi}{6}=\frac{6\pi+4\pi}{24}=\frac{10}{24}\pi=\frac{5}{12}\pi

we have that

4\cdot\text{cis(}\frac{\pi}{4})\cdot5\text{cis(}\frac{\pi}{6})=20cis(\frac{5\pi}{12})

Therefore, the answer is the second option from top to bottom.

3 0
11 months ago
13x + 15=17x-13 solve for the solution
Archy [21]

Answer: x=7

Step-by-step explanation:

Step 1: Subtract 17x from both sides.

13x+15−17x=17x−13−17x

−4x+15=−13

Step 2: Subtract 15 from both sides.

−4x+15−15=−13−15

−4x=−28

Step 3: Divide both sides by -4.

−4x/−4 =−28/−4

x=7

6 0
3 years ago
What is the LCD for the fractions 1/3, 3/4, 5/32 and 89?
Leni [432]
Your answer would be 288. Also, did you mean 8/9? Hope I helped!
6 0
2 years ago
Complete the identity. sin4x - cos4x = ?
Katyanochek1 [597]
Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
4 0
3 years ago
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If the diagonals of a quadrilateral bisect the angles, is the quadrilateral always a parallelogram? Explain your answer.
Liula [17]
Yes. If the diagonals bisect the angles, the quadrilateral is always a parallelogram, specifically, a rhombus.


Consider quadrilateral ABCD. If diagonal AC bisects angles A and C, then ΔACB is congruent to ΔACD (ASA). Hence AB=AD and BC=CD (CPCTC).

Likewise, if diagonal BD bisects angles B and D, triangles BDA and BDC are congruent, thus AB=BC and AD=CD. (CPCTC again). Now, we have AB=BC=CD=AD, so the figure is a rhombus, hence a parallelogram.
6 0
2 years ago
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