Answer:
They are taking 12 2 credit courses
The are taking 4 1 credit courses
Step-by-step explanation:
x = 1 credit courses
y = 2 credit courses
The number of courses is 16
x+y = 16
The number of credits is 28 so multiply the course by the number of credits
1x+2y=28
Subtract the first equation from the second equation
x+2y =28
-x-y=-16
-----------------
y = 12
They are taking 12 2 credit courses
We still need to find the 1 credit courses
x+y = 16
x+12= 16
Subtract 12 from each side
x-12-12 = 16-12
x =4
The are taking 4 1 credit courses
Adding the systems of equations together, we get
2x=88
Dividing both sides by 2, we get x, or the number of women, to be 44.
Plugging that into either equation, we get
44-y=18. Adding y to both sides and subtracting 18, we get y, or the number of men, to be 26.
Feel free to ask further questions!
Answer: 10
Step-by-step explanation: 6 divided by 120 = 60 ÷ 6 = 10
Answer:
ASA
Step-by-step explanation:
They give us one pair of angles and one pair of congruent sides for it to be ASA we need an additional angle but on the other side from where the last angle was. By vertical angles proof we can see that the angles at the intersection will be congruent so you have one angle then a side then another angle
Hope This Helps :)
