If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.
So, what are the chances of it not occurring in 1 trip?
1−.37=.63
What about not occurring in 2 trips?
(1−.37)⋅(1−.37)=.63⋅.63=.3969
Now what about not occurring in 4 trips?
.63^4 = 0.15752961
We must subtract this value from 1
(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:
1−0.15752961 = .84247039
TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.
5x - y = 3 ------------ (1)
6x - y = 8 ------------ (2)
From (1):
5x - y = 3
y = 5x - 3 ------------ Sub into (2)
6x - (5x - 3) = 8
6x - 5x + 3 = 8
x + 3 = 8
x = 5 ------------------- Sub into (1)
5x - y = 3
5(5) - y = 3
25 - y = 3
y = 25 - 3
y = 22
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Ans: x = 5, y = 22
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Answer:
there were 200 children and 500 adults at the show
Step-by-step explanation:
7x+10y=6400
x+y=700
x=700-y
7(700-y)+10y=6400
4900-7y+10y=6400
-7y+10y=1500
3y=1500
y=500
x=700-y
x=700-500
x=200
Answer:
from least to greatest 112 121 124 137 147 156 173 189
Step-by-step explanation:
if you subtract each number from a number that is greater than all the numbers for example 200 then what ever has the most left will be greatest and least will be least for example 121 - 200 is negative 79 and 189 - 200 is negative 11 negative 11 is higher so its a greater number there is also easier ways to do this but this is just extra