Question

Coordinate point A located at (9,4) was translated up 3 units and right 6 units, it is then dillated by a scale factor of 2 and reflected across the x axis.Coordinate point A located at (9,4) was translated up 3 units and right 6 units, it is then dilated by a scale factor of 2 and reflected across the x axis.

Answer 1

The image after the sequence of transformations is (30, -14)

What is the image of the point after the sequence of transformations?

We start with the point (9, 4), first we need to translate it up 3 units, then right 6 units, dilate it by a scale factor of 2, and finally reflect it across the x-axis.

Let's write all these transformations in a general way and then let's apply them.

For a general point (x, y)

A vertical translation up of 3 units gives: (x, y + 3)

A horizontal translation of 6 units to the right gives: (x + 6, y)

A dilation of scale factor 2 gives: (2x, 2y)

A reflection across the x-axis gives: (x, -y)

Then if we apply all that to our point (9, 4) we will get:

A vertical translation up of 3 units gives: (9, 4 + 3) = (9, 7)

A horizontal translation of 6 units to the right gives: (9 + 6, 7) = (15, 7)

A dilation of scale factor 2 gives: (2*15, 2*7) = (30, 14)

A reflection across the x-axis gives: (30, -14)

That is the image after the sequence of transformations.

Learn more about transformations by reading:

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