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VladimirAG [237]
3 years ago
9

Whats the surface area of 2"long , 2""wide, 2" high?​

Mathematics
1 answer:
Alex73 [517]3 years ago
5 0

Answer:

8

Step-by-step explanation:

2 times 2 times 2=8

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The slant asymptote of f(x)=
nekit [7.7K]

Answer: It is true, I explained it down below in the picture.

Step-by-step explanation:

7 0
3 years ago
a shopkeeper buys cocacola 60 rupees a dozen and sell 6 rupees per bottle find his profit or loss persentage​
Lady_Fox [76]

Answer:

20%

Step-by-step explanation:

12 bottle is 60 rupees

each sold 6 ruppes

so 12 bottle cost 72 ruppes

12*100/60 = 20%

8 0
3 years ago
Read 2 more answers
2=5x+4-3+5-1 what is the answer for this question
klio [65]
The answer will be x= -3/5
3 0
4 years ago
Can someone plz help me... it would be great if u did all three questions
Artyom0805 [142]
1: 48
2: 18
3: 73
Hope this helps you!
4 0
3 years ago
Read 2 more answers
Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati
Brrunno [24]
Remember that <span>an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.
 
Lets solve our equation to find out what is the extraneous solution:
</span>\sqrt{x-3} =x-5
(\sqrt{x-3})^2 =(x-5)^2
x-3=x^2-10x+25
x^2-11x+28=0
(x-4)(x-7)=0
x-4=0 and x-7=0
x=4 and x=7
<span>
So, the solutions of our equation are </span>x=4 and x=7. Lets replace each solution in our original equation to check if they are valid solutions:
- For x=7
\sqrt{x-3} =x-5
\sqrt{7-3} =7-5
\sqrt{4} =2
2=2
We can conclude that 7 is a valid solution of the equation.

- For x=4
\sqrt{x-3} =x-5
\sqrt{4-3} =4-5
\sqrt{1} =1
1 \neq 1
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: <span>D. the extraneous solution is x = 4</span>
7 0
3 years ago
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