<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Answer:
4 dollars
7 dimes or $4.70.
Step-by-step explanation:
The 4 dollars, 12 dimes, and 10 pennies added up together is $5.30. You will subtract that from $10.00 and you will get $4.70. That will be 4 dollars and 7 dimes left that is needed, or $4.70.
Answer:
A) added to both sides of the equation
Step-by-step explanation:
Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.
<h3>What is Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is ![f(x+1) = \dfrac{5}{2}[f(x)]](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D)
, therefore, in order to find the value of f(5), we need to calculate the value of f(4).
f(2)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(2)=f(1+1) = \dfrac{5}{2}[f(1)]\\\\f(2) = 2.5 \times 3.2\\\\f(2) = 8](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%282%29%3Df%281%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%281%29%5D%5C%5C%5C%5Cf%282%29%20%3D%202.5%20%5Ctimes%203.2%5C%5C%5C%5Cf%282%29%20%3D%208)
f(3)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(3)=f(2+1) = \dfrac{5}{2}[f(2)]\\\\f(3) = 2.5 \times 8\\\\f(3) = 20](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%283%29%3Df%282%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%282%29%5D%5C%5C%5C%5Cf%283%29%20%3D%202.5%20%5Ctimes%208%5C%5C%5C%5Cf%283%29%20%3D%2020)
f(4)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%284%29%3Df%283%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%283%29%5D%5C%5C%5C%5Cf%284%29%20%3D%202.5%20%5Ctimes%2020%5C%5C%5C%5Cf%284%29%20%3D%2050)
f(5)
![f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125](https://tex.z-dn.net/?f=f%28x%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%28x%29%5D%5C%5C%5C%5Cf%285%29%3Df%284%2B1%29%20%3D%20%5Cdfrac%7B5%7D%7B2%7D%5Bf%284%29%5D%5C%5C%5C%5Cf%285%29%20%3D%202.5%20%5Ctimes%2050%5C%5C%5C%5Cf%285%29%20%3D%20125)
Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.
Learn more about Function:
brainly.com/question/5245372
