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agasfer [191]
3 years ago
12

Larry says the 9 in 198,550 is 10 times greater than 9 in 4,931 agree or disagree ... how am I supposed to help figure that out

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
Disagree
10
100
1000
10000

9
90
930 this is definitely not ten times the 9 
9000
98000
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Please help guys!!!!!!!!!!!!!!
hram777 [196]

Answer:

a) x = -10

b) x = 7

Step-by-step explanation:

a)

2(x + 3) = x - 4

2x + 6 = x - 4

2x - x = -4 - 6

x = -10

b)

4(5x - 2) = 2(9x + 3)

20x - 8 = 18x + 6

20x - 18x = 6 + 8

2x = 14

x = 7

7 0
2 years ago
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Help me out here guys
kvasek [131]
D.

f(x) can be written as (x+2)(x-2)(x-1)
by using difference of two squares to expand x^2 - 4 whch yields 3 x intercepts

similarly, k(x) can be written as
x(x+5)(x-5) which also yields 3
x intercepts (0,-5, and 5)
3 0
2 years ago
The base of a prism are right triangles with leg lengths of 7 inches and 5 inches. the prism height is 12 inches. what is the vo
Wewaii [24]
The volume formula is length x width x height. 7x5x12=420 cubic inches
4 0
2 years ago
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Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
You have a recipe that calls for 3 eggs for every 2 cups of flour. You use 12 eggs. How much flour do you need?
WINSTONCH [101]
You use 8   cups of flour

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3 years ago
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