$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
Answer:
Sample Response: Perform the transformations from right to left. First, rotate the triangle 90 degrees. Negate the y-coordinate and then switch the coordinates to get (–1, 0). Next, perform the translation up by adding 0 to the x-coordinate and 2 to the y-coordinate to get (–1, 2). Finally, reflect this point over the y-axis by negating the x-coordinate to get (1, 2).
Step-by-step explanation:
5^2 + 12^2 = c^2
25 + 144 = c^2
169 = c^2
take the square root of both sides
+ - 13 = c
Answer:
The null hypothesis will be that the average annual donor income is less or equal to $ 100,000
Step-by-step explanation:
The claim is mostly treated as alternate hypothesis .
In this question the claim is given as the average annual donor income has increased therefore it is written as
Ha: u > 100,000
The null hypothesis is reverse of the alternate hypothesis
H0: u ≤ 100,000
The null hypothesis will be that the average annual donor income is less or equal to $ 100,000
<span>As the age of the U-235 sample is 2.631 billion years, and the half-life of U-235 is 713 million years, the sample has undergone 2.361 X 1,000,000,000 / 713 X 1,000,000 = 3.69 half lives. In each half-life the sample reduces to half its original weight according to the radioactive Half-Life Formula:
ln (Nt /N0) = -kt, where N0 = mass of the original weight of radioactive material, Nt = mass of radioactive material at time t, k = decay constant and t = time interval . We have to put Nt/N0 = 1/2 for time interval = half-life.</span>
