This is Super Confusing to me

If it is assumed that the heights of men are normally distributed with a standard deviation of 2.5 inches, how large a sample sh

Volgvan

Answer:

30 men

Step-by-step explanation:

In order to be sure that the sample mean does differ from the population mean by more than 0.90, the sample size (n) that should be used is given by:

$0.90 < Z\frac{s}{\sqrt{n}}$

Where 'Z' , for a 95% probability is 1.960, 's' is the standard deviation of 2.5 inches:

$0.90 > 1.960\frac{2.5}{\sqrt{n}}\\n >(\frac{1.960*2.5}{0.9})^2\\n>29.64$

Rounding up to the nearest whole number, the sample size should be at least 30 men.

7 0

3 years ago

Mallory puts $1.00 in a jar. The following week, she puts 2 times that original amount in the jar. For each of the next six week

Burka [1]

The relationship of the ordered pair that represents Mallory savings is a nonlinear relationship.

Let x represents the number of weeks, and y represents the amount put in the jar, each week.

So, we have the following highlights for 6 weeks.

Week 1: (1, 1)
Week 2: (2,2)
Week 3: (3,4)
Week 4: (4,8)
Week 5: (5,16)
Week 6: (6,32)

The ordered pairs can then be represented as:

$(x,y) = (1,1)(2,2)(3,4)(4,8)(5,16)(6,32)$

As the x values increase, the y values increase too, but the y values do not increase at a constant rate.

This means that the relationship is not linear; it is an exponential relationship.

Hence, the relationship is a nonlinear relationship.

Read more about linear relationships at:

brainly.com/question/7040405

8 0

2 years ago

Read 2 more answers

Help! Need by 10:30 to turn in and I'm confused!

Alecsey [184]

Answer:

8 boxes of tissues

5 bags of cough drops

Step-by-step explanation:

You need to write a system of equations.

x = number of tissue boxes

y = number of cough drop bags

x (number of tissue boxes) + y (number of cough drop bags) = 13 (total number of tissues and cough drops combined.

So, your first equation is

x + y = 13

Then, you need to write the second equation.

(1.69 [cost of 1 tissue box] * [number of tissue boxes]) + (1.19 [cost of one bag of cough drops] * [number of cough drop bags] = 19.47 [total cost of tissues and cough drops]

That's a lot to read, so here's the equation simplified!

1.69x + 1.19y = 19.47

Now, you have two equations:

x + y = 13

1.69x + 1.19y = 19.47

I would solve with the substitution method.

the first equation can be changed to x = 13 - y by subtracting y from both sides.

Then, your two equations are:

x = 13 - y

1.69x + 1.19y = 19.47

Now, you can plug in that value of x into the second equation!

1.69(13 - y) + 1.19y = 19.47

21.97 - 1.69y + 1.19y = 19.47

subtract 21.97 from both sides

-1.69y + 1.19y = -2.5

Add the y values

-0.5y = -2.5

divide both sides by -0.5

so, y equals 5 bags of cough drops

now that you know what y equals, plug it back into your original equation to find x!

x + y = 13

plug in y

x + 5 = 13

x = 8

so, x = 8 boxes of tissues

Hope this helps! Let me know if you have any questions!

8 0

3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

3 years ago

9. An express delivery service advertises next-day delivery of any parcel it receives before 3PM. The actual success rate is 90%

Juli2301 [7.4K]

Answer:

a) P(X =16 ) = 0.1853

b) $P(X \leq 12)$ = 0.0684

Step-by-step explanation:

GIVEN DATA:

n = 16

p = 0.90

from relation given probabllity can be solve

$P(X) = ^nC_x * p^x * ( 1 - p)^{n-x}$

a)

$P(X =16 ) = ^{16}C_{16} * 0.90^x * ( 1 - 0.90)^{16-16}$

P(X =16 ) = 0.1853

b) $P(X \leq 12) = 1 - P(X \geq 13)$

= 1 - [ P(X = 13) +P(X = 14) +P(X = 15) +P(X = 16) ]

$= 1 - [ ^{16}C_{13} * 0.90^{13} * (1 - 0.90)^3 +^{16}C_{14} * 0.90^{14} * (1 - 0.90)^2 +^{16}C_{15} * 0.90^{15} * (1 - 0.90)^1 +^{16}C_{16} * 0.90^{16} * (1 - 0.90)^0 ]$

= 0.0684

4 0

3 years ago